Solve for x
x=\frac{3y}{4}+\frac{1}{2}
Solve for y
y=\frac{4x-2}{3}
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-4x=-2-3y
Subtract 3y from both sides.
-4x=-3y-2
The equation is in standard form.
\frac{-4x}{-4}=\frac{-3y-2}{-4}
Divide both sides by -4.
x=\frac{-3y-2}{-4}
Dividing by -4 undoes the multiplication by -4.
x=\frac{3y}{4}+\frac{1}{2}
Divide -2-3y by -4.
3y=-2+4x
Add 4x to both sides.
3y=4x-2
The equation is in standard form.
\frac{3y}{3}=\frac{4x-2}{3}
Divide both sides by 3.
y=\frac{4x-2}{3}
Dividing by 3 undoes the multiplication by 3.
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