Solve -4t^3+2t^2-1/t

$$- 4 t ^ { 3 } + 2 t ^ { 2 } - \frac { 1 } { t }$$

Evaluate

$$-4t^{3}+2t^{2}-\frac{1}{t}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply -4t^{3}+2t^{2} times \frac{t}{t}.

$$\frac{\left(-4t^{3}+2t^{2}\right)t}{t}-\frac{1}{t}$$

Since \frac{\left(-4t^{3}+2t^{2}\right)t}{t} and \frac{1}{t} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\left(-4t^{3}+2t^{2}\right)t-1}{t}$$

Do the multiplications in \left(-4t^{3}+2t^{2}\right)t-1.

$$\frac{-4t^{4}+2t^{3}-1}{t}$$

Factor

$$-\frac{4t^{4}-2t^{3}+1}{t}$$