Solve -4a+1>9+3(2a+1)+a

$$- 4 a + 1 > 9 + 3 ( 2 a + 1 ) + a$$

Solve for a

$$a<-1$$

Solution Steps

Use the distributive property to multiply 3 by 2a+1.

$$-4a+1>9+6a+3+a$$

Add 9 and 3 to get 12.

$$-4a+1>12+6a+a$$

Combine 6a and a to get 7a.

$$-4a+1>12+7a$$

Subtract 7a from both sides.

$$-4a+1-7a>12$$

Combine -4a and -7a to get -11a.

$$-11a+1>12$$

Subtract 1 from both sides.

$$-11a>12-1$$

Subtract 1 from 12 to get 11.

$$-11a>11$$

Divide both sides by -11. Since -11 is negative, the inequality direction is changed.

$$a<\frac{11}{-11}$$

Divide 11 by -11 to get -1.

$$a<-1$$