Solve -4-2*(-5)-6:2-4*2-5+7*3

$$- 4 - 2 \cdot ( - 5 ) - 6 : 2 - 4 \cdot 2 - 5 + 7 \cdot 3$$

Evaluate

$$11$$

Solution Steps

Multiply 2 and -5 to get -10.

$$-4-\left(-10\right)-\frac{6}{2}-4\times 2-5+7\times 3$$

The opposite of -10 is 10.

$$-4+10-\frac{6}{2}-4\times 2-5+7\times 3$$

Add -4 and 10 to get 6.

$$6-\frac{6}{2}-4\times 2-5+7\times 3$$

Divide 6 by 2 to get 3.

$$6-3-4\times 2-5+7\times 3$$

Subtract 3 from 6 to get 3.

$$3-4\times 2-5+7\times 3$$

Multiply 4 and 2 to get 8.

$$3-8-5+7\times 3$$

Subtract 8 from 3 to get -5.

$$-5-5+7\times 3$$

Subtract 5 from -5 to get -10.

$$-10+7\times 3$$

Multiply 7 and 3 to get 21.

$$-10+21$$

Add -10 and 21 to get 11.

$$11$$

Factor

$$11$$