Solve -4(x-2)+3<4x-5-5x

$$- 4 ( x - 2 ) + 3 < 4 x - 5 - 5 x$$

Solve for x

$$x>\frac{16}{3}$$

Solution Steps

Use the distributive property to multiply -4 by x-2.

$$-4x+8+3<4x-5-5x$$

Add 8 and 3 to get 11.

$$-4x+11<4x-5-5x$$

Combine 4x and -5x to get -x.

$$-4x+11<-x-5$$

Add x to both sides.

$$-4x+11+x<-5$$

Combine -4x and x to get -3x.

$$-3x+11<-5$$

Subtract 11 from both sides.

$$-3x<-5-11$$

Subtract 11 from -5 to get -16.

$$-3x<-16$$

Divide both sides by -3. Since -3 is negative, the inequality direction is changed.

$$x>\frac{-16}{-3}$$

Fraction \frac{-16}{-3} can be simplified to \frac{16}{3} by removing the negative sign from both the numerator and the denominator.

$$x>\frac{16}{3}$$