Solve -4(-5-b)=1/3(b+16)

$$- 4 ( - 5 - b ) = \frac { 1 } { 3 } ( b + 16 )$$

Solve for b

$$b=-4$$

Steps for Solving Linear Equation

Use the distributive property to multiply -4 by -5-b.

$$20+4b=\frac{1}{3}\left(b+16\right)$$

Use the distributive property to multiply \frac{1}{3} by b+16.

$$20+4b=\frac{1}{3}b+\frac{1}{3}\times 16$$

Multiply \frac{1}{3} and 16 to get \frac{16}{3}.

$$20+4b=\frac{1}{3}b+\frac{16}{3}$$

Subtract \frac{1}{3}b from both sides.

$$20+4b-\frac{1}{3}b=\frac{16}{3}$$

Combine 4b and -\frac{1}{3}b to get \frac{11}{3}b.

$$20+\frac{11}{3}b=\frac{16}{3}$$

Subtract 20 from both sides.

$$\frac{11}{3}b=\frac{16}{3}-20$$

Convert 20 to fraction \frac{60}{3}.

$$\frac{11}{3}b=\frac{16}{3}-\frac{60}{3}$$

Since \frac{16}{3} and \frac{60}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{11}{3}b=\frac{16-60}{3}$$

Subtract 60 from 16 to get -44.

$$\frac{11}{3}b=-\frac{44}{3}$$

Multiply both sides by \frac{3}{11}, the reciprocal of \frac{11}{3}.

$$b=-\frac{44}{3}\times \frac{3}{11}$$

Multiply -\frac{44}{3} times \frac{3}{11} by multiplying numerator times numerator and denominator times denominator.

$$b=\frac{-44\times 3}{3\times 11}$$

Cancel out 3 in both numerator and denominator.

$$b=\frac{-44}{11}$$

Divide -44 by 11 to get -4.

$$b=-4$$