Solve -43/9-71/6=

$$- 4 \frac { 3 } { 9 } - 7 \frac { 1 } { 6 } =$$

Evaluate

$$-\frac{23}{2}=-11.5$$

Solution Steps

Multiply 4 and 9 to get 36.

$$-\frac{36+3}{9}-\frac{7\times 6+1}{6}$$

Add 36 and 3 to get 39.

$$-\frac{39}{9}-\frac{7\times 6+1}{6}$$

Reduce the fraction \frac{39}{9} to lowest terms by extracting and canceling out 3.

$$-\frac{13}{3}-\frac{7\times 6+1}{6}$$

Multiply 7 and 6 to get 42.

$$-\frac{13}{3}-\frac{42+1}{6}$$

Add 42 and 1 to get 43.

$$-\frac{13}{3}-\frac{43}{6}$$

Least common multiple of 3 and 6 is 6. Convert -\frac{13}{3} and \frac{43}{6} to fractions with denominator 6.

$$-\frac{26}{6}-\frac{43}{6}$$

Since -\frac{26}{6} and \frac{43}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-26-43}{6}$$

Subtract 43 from -26 to get -69.

$$\frac{-69}{6}$$

Reduce the fraction \frac{-69}{6} to lowest terms by extracting and canceling out 3.

$$-\frac{23}{2}$$

Factor

$$-\frac{23}{2} = -11\frac{1}{2} = -11.5$$