Solve -41/6-07+28/9div(-7/12)

$$- 4 \frac { 1 } { 6 } - \frac { 07 + 28 } { 9 } \div ( - \frac { 7 } { 12 } )$$

Evaluate

$$\frac{7}{6}\approx 1.166666667$$

Solution Steps

Multiply 4 and 6 to get 24.

$$-\frac{24+1}{6}-\frac{\frac{0\times 7+28}{9}}{-\frac{7}{12}}$$

Add 24 and 1 to get 25.

$$-\frac{25}{6}-\frac{\frac{0\times 7+28}{9}}{-\frac{7}{12}}$$

Divide \frac{0\times 7+28}{9} by -\frac{7}{12} by multiplying \frac{0\times 7+28}{9} by the reciprocal of -\frac{7}{12}.

$$-\frac{25}{6}-\frac{\left(0\times 7+28\right)\times 12}{9\left(-7\right)}$$

Cancel out 3 in both numerator and denominator.

$$-\frac{25}{6}-\frac{4\times 28}{-7\times 3}$$

Multiply 4 and 28 to get 112.

$$-\frac{25}{6}-\frac{112}{-7\times 3}$$

Multiply -7 and 3 to get -21.

$$-\frac{25}{6}-\frac{112}{-21}$$

Reduce the fraction \frac{112}{-21} to lowest terms by extracting and canceling out 7.

$$-\frac{25}{6}-\left(-\frac{16}{3}\right)$$

The opposite of -\frac{16}{3} is \frac{16}{3}.

$$-\frac{25}{6}+\frac{16}{3}$$

Least common multiple of 6 and 3 is 6. Convert -\frac{25}{6} and \frac{16}{3} to fractions with denominator 6.

$$-\frac{25}{6}+\frac{32}{6}$$

Since -\frac{25}{6} and \frac{32}{6} have the same denominator, add them by adding their numerators.

$$\frac{-25+32}{6}$$

Add -25 and 32 to get 7.

$$\frac{7}{6}$$

Factor

$$\frac{7}{2 \cdot 3} = 1\frac{1}{6} = 1.1666666666666667$$