Solve -41/6-0.7+2.8/9div(-7/12)

$$- 4 \frac { 1 } { 6 } - \frac { 0.7 + 2.8 } { 9 } \div ( - \frac { 7 } { 12 } )$$

Evaluate

$$-3.5$$

Solution Steps

Multiply 4 and 6 to get 24.

$$-\frac{24+1}{6}-\frac{\frac{0.7+2.8}{9}}{-\frac{7}{12}}$$

Add 24 and 1 to get 25.

$$-\frac{25}{6}-\frac{\frac{0.7+2.8}{9}}{-\frac{7}{12}}$$

Divide \frac{0.7+2.8}{9} by -\frac{7}{12} by multiplying \frac{0.7+2.8}{9} by the reciprocal of -\frac{7}{12}.

$$-\frac{25}{6}-\frac{\left(0.7+2.8\right)\times 12}{9\left(-7\right)}$$

Cancel out 3 in both numerator and denominator.

$$-\frac{25}{6}-\frac{4\left(0.7+2.8\right)}{-7\times 3}$$

Add 0.7 and 2.8 to get 3.5.

$$-\frac{25}{6}-\frac{4\times 3.5}{-7\times 3}$$

Multiply 4 and 3.5 to get 14.

$$-\frac{25}{6}-\frac{14}{-7\times 3}$$

Multiply -7 and 3 to get -21.

$$-\frac{25}{6}-\frac{14}{-21}$$

Reduce the fraction \frac{14}{-21} to lowest terms by extracting and canceling out 7.

$$-\frac{25}{6}-\left(-\frac{2}{3}\right)$$

The opposite of -\frac{2}{3} is \frac{2}{3}.

$$-\frac{25}{6}+\frac{2}{3}$$

Least common multiple of 6 and 3 is 6. Convert -\frac{25}{6} and \frac{2}{3} to fractions with denominator 6.

$$-\frac{25}{6}+\frac{4}{6}$$

Since -\frac{25}{6} and \frac{4}{6} have the same denominator, add them by adding their numerators.

$$\frac{-25+4}{6}$$

Add -25 and 4 to get -21.

$$\frac{-21}{6}$$

Reduce the fraction \frac{-21}{6} to lowest terms by extracting and canceling out 3.

$$-\frac{7}{2}$$

Factor

$$-3.5$$