Solve -4+(-2+1)+5*[3-(1-2+2+2-(5-6-1)+2)]

$$- 4 + ( - 2 + 1 ) + 5 \cdot [ 3 - ( 1 - 2 + 2 + 2 - ( 5 - 6 - 1 ) + 2 ) ]$$

Evaluate

$$-25$$

Solution Steps

Subtract 2 from -4 to get -6.

$$-6+1+5\left(3-\left(1-2+2+2-\left(5-6-1\right)+2\right)\right)$$

Add -6 and 1 to get -5.

$$-5+5\left(3-\left(1-2+2+2-\left(5-6-1\right)+2\right)\right)$$

Subtract 2 from 1 to get -1.

$$-5+5\left(3-\left(-1+2+2-\left(5-6-1\right)+2\right)\right)$$

Add -1 and 2 to get 1.

$$-5+5\left(3-\left(1+2-\left(5-6-1\right)+2\right)\right)$$

Add 1 and 2 to get 3.

$$-5+5\left(3-\left(3-\left(5-6-1\right)+2\right)\right)$$

Subtract 6 from 5 to get -1.

$$-5+5\left(3-\left(3-\left(-1-1\right)+2\right)\right)$$

Subtract 1 from -1 to get -2.

$$-5+5\left(3-\left(3-\left(-2\right)+2\right)\right)$$

The opposite of -2 is 2.

$$-5+5\left(3-\left(3+2+2\right)\right)$$

Add 3 and 2 to get 5.

$$-5+5\left(3-\left(5+2\right)\right)$$

Add 5 and 2 to get 7.

$$-5+5\left(3-7\right)$$

Subtract 7 from 3 to get -4.

$$-5+5\left(-4\right)$$

Multiply 5 and -4 to get -20.

$$-5-20$$

Subtract 20 from -5 to get -25.

$$-25$$

Factor

$$-25$$