Solve for x
x\leq \frac{4}{3}
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36x\leq 11+37
Add 37 to both sides.
36x\leq 48
Add 11 and 37 to get 48.
x\leq \frac{48}{36}
Divide both sides by 36. Since 36 is positive, the inequality direction remains the same.
x\leq \frac{4}{3}
Reduce the fraction \frac{48}{36} to lowest terms by extracting and canceling out 12.
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