Solve -32-|(-5)|*-18div|-(-3)|

$$- 32 - | ( - 5 ) | \times - 18 \div | - ( - 3 ) |$$

Evaluate

$$-2$$

Solution Steps

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -5 is 5.

$$-32-\frac{5\left(-18\right)}{|-\left(-3\right)|}$$

Multiply 5 and -18 to get -90.

$$-32-\frac{-90}{|-\left(-3\right)|}$$

The opposite of -3 is 3.

$$-32-\frac{-90}{|3|}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 3 is 3.

$$-32-\frac{-90}{3}$$

Divide -90 by 3 to get -30.

$$-32-\left(-30\right)$$

The opposite of -30 is 30.

$$-32+30$$

Add -32 and 30 to get -2.

$$-2$$

Factor

$$-2$$