Solve -3.6geq-0.3a+1.2

$$- 3.6 \geq - 0.3 a + 1.2$$

Solve for a

$$a\geq 16$$

Solution Steps

Swap sides so that all variable terms are on the left hand side. This changes the sign direction.

$$-0.3a+1.2\leq -3.6$$

Subtract 1.2 from both sides.

$$-0.3a\leq -3.6-1.2$$

Subtract 1.2 from -3.6 to get -4.8.

$$-0.3a\leq -4.8$$

Divide both sides by -0.3. Since -0.3 is negative, the inequality direction is changed.

$$a\geq \frac{-4.8}{-0.3}$$

Expand \frac{-4.8}{-0.3} by multiplying both numerator and the denominator by 10.

$$a\geq \frac{-48}{-3}$$

Divide -48 by -3 to get 16.

$$a\geq 16$$