Solve -3,6-1,9t+1,2+5,1t

$$- 3,6 - 1,9 t + 1,2 + 5,1 t$$

Evaluate

$$\frac{16t-12}{5}$$

Solution Steps

Add -3,6 and 1,2 to get -2,4.

$$-2,4-1,9t+5,1t$$

Combine -1,9t and 5,1t to get 3,2t.

$$-2,4+3,2t$$

Differentiate w.r.t. t

$$3,2$$

Steps Using Derivative Rule for Sum

Add -3,6 and 1,2 to get -2,4.

$$\frac{\mathrm{d}}{\mathrm{d}t}(-2,4-1,9t+5,1t)$$

Combine -1,9t and 5,1t to get 3,2t.

$$\frac{\mathrm{d}}{\mathrm{d}t}(-2,4+3,2t)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$3,2t^{1-1}$$

Subtract 1 from 1.

$$3,2t^{0}$$

For any term t except 0, t^{0}=1.

$$3,2\times 1$$

For any term t, t\times 1=t and 1t=t.

$$3,2$$