Solve for x
x=-3y^{2}+6y-1
Solve for y (complex solution)
y=-\frac{\sqrt{6-3x}}{3}+1
y=\frac{\sqrt{6-3x}}{3}+1
Solve for y
y=-\frac{\sqrt{6-3x}}{3}+1
y=\frac{\sqrt{6-3x}}{3}+1\text{, }x\leq 2
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6y-x-1=3y^{2}
Add 3y^{2} to both sides. Anything plus zero gives itself.
-x-1=3y^{2}-6y
Subtract 6y from both sides.
-x=3y^{2}-6y+1
Add 1 to both sides.
\frac{-x}{-1}=\frac{3y^{2}-6y+1}{-1}
Divide both sides by -1.
x=\frac{3y^{2}-6y+1}{-1}
Dividing by -1 undoes the multiplication by -1.
x=-3y^{2}+6y-1
Divide 3y^{2}-6y+1 by -1.
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Limits
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