Solve -3xy^2-(-4x*7y^2)+[8x^2y^3:(2xy)]=

$$- 3 x y ^ { 2 } - ( - 4 x \cdot 7 y ^ { 2 } ) + [ 8 x ^ { 2 } y ^ { 3 } : ( 2 x y ) ] =$$

Evaluate

$$29xy^{2}$$

Solution Steps

Multiply -4 and 7 to get -28.

$$-3xy^{2}-\left(-28xy^{2}\right)+\frac{8x^{2}y^{3}}{2xy}$$

The opposite of -28xy^{2} is 28xy^{2}.

$$-3xy^{2}+28xy^{2}+\frac{8x^{2}y^{3}}{2xy}$$

Combine -3xy^{2} and 28xy^{2} to get 25xy^{2}.

$$25xy^{2}+\frac{8x^{2}y^{3}}{2xy}$$

Cancel out 2xy in both numerator and denominator.

$$25xy^{2}+4xy^{2}$$

Combine 25xy^{2} and 4xy^{2} to get 29xy^{2}.

$$29xy^{2}$$

Differentiate w.r.t. x

$$29y^{2}$$