Solve for x
x=\frac{7}{3}-y
Solve for y
y=\frac{7}{3}-x
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-3x+7=3y
Add 3y to both sides. Anything plus zero gives itself.
-3x=3y-7
Subtract 7 from both sides.
\frac{-3x}{-3}=\frac{3y-7}{-3}
Divide both sides by -3.
x=\frac{3y-7}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{7}{3}-y
Divide 3y-7 by -3.
-3y+7=3x
Add 3x to both sides. Anything plus zero gives itself.
-3y=3x-7
Subtract 7 from both sides.
\frac{-3y}{-3}=\frac{3x-7}{-3}
Divide both sides by -3.
y=\frac{3x-7}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{7}{3}-x
Divide 3x-7 by -3.
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