Solve for x
x=-\frac{2y}{3}-4
Solve for y
y=-\frac{3x}{2}-6
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-3x=12+2y
Add 2y to both sides.
-3x=2y+12
The equation is in standard form.
\frac{-3x}{-3}=\frac{2y+12}{-3}
Divide both sides by -3.
x=\frac{2y+12}{-3}
Dividing by -3 undoes the multiplication by -3.
x=-\frac{2y}{3}-4
Divide 12+2y by -3.
-2y=12+3x
Add 3x to both sides.
-2y=3x+12
The equation is in standard form.
\frac{-2y}{-2}=\frac{3x+12}{-2}
Divide both sides by -2.
y=\frac{3x+12}{-2}
Dividing by -2 undoes the multiplication by -2.
y=-\frac{3x}{2}-6
Divide 12+3x by -2.
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