Solve -3x^2-18x-y-24=0

$$- 3 x ^ { 2 } - 18 x - y - 24 = 0$$

Solve for y

$$y=-3\left(x+2\right)\left(x+4\right)$$

Steps for Solving Linear Equation

Add 3x^{2} to both sides. Anything plus zero gives itself.

$$-18x-y-24=3x^{2}$$

Add 18x to both sides.

$$-y-24=3x^{2}+18x$$

Add 24 to both sides.

$$-y=3x^{2}+18x+24$$

Divide both sides by -1.

$$\frac{-y}{-1}=\frac{3\left(x+2\right)\left(x+4\right)}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$y=\frac{3\left(x+2\right)\left(x+4\right)}{-1}$$

Divide 3\left(2+x\right)\left(4+x\right) by -1.

$$y=-3\left(x+2\right)\left(x+4\right)$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{9-3y}}{3}-3$$

$$x=\frac{\sqrt{9-3y}}{3}-3$$

Solve for x

$$x=-\frac{\sqrt{9-3y}}{3}-3$$

$$x=\frac{\sqrt{9-3y}}{3}-3\text{, }y\leq 3$$