Solve for x
x=\frac{y-3}{3}
Solve for y
y=3\left(x+1\right)
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-3x=3-y
The equation is in standard form.
\frac{-3x}{-3}=\frac{3-y}{-3}
Divide both sides by -3.
x=\frac{3-y}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{y}{3}-1
Divide 3-y by -3.
3-y=-3x
Swap sides so that all variable terms are on the left hand side.
-y=-3x-3
Subtract 3 from both sides.
\frac{-y}{-1}=\frac{-3x-3}{-1}
Divide both sides by -1.
y=\frac{-3x-3}{-1}
Dividing by -1 undoes the multiplication by -1.
y=3x+3
Divide -3x-3 by -1.
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