Solve for x
x=\frac{y-12}{3}
Solve for y
y=3\left(x+4\right)
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-3x=12-y
Subtract y from both sides.
\frac{-3x}{-3}=\frac{12-y}{-3}
Divide both sides by -3.
x=\frac{12-y}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{y}{3}-4
Divide 12-y by -3.
y=12+3x
Add 3x to both sides.
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Limits
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