Solve for x
x=\frac{8y-23}{3}
Solve for y
y=\frac{3x+23}{8}
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-3x=23-8y
Subtract 8y from both sides.
\frac{-3x}{-3}=\frac{23-8y}{-3}
Divide both sides by -3.
x=\frac{23-8y}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{8y-23}{3}
Divide 23-8y by -3.
8y=23+3x
Add 3x to both sides.
8y=3x+23
The equation is in standard form.
\frac{8y}{8}=\frac{3x+23}{8}
Divide both sides by 8.
y=\frac{3x+23}{8}
Dividing by 8 undoes the multiplication by 8.
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