Solve for x
x=\frac{8y}{3}-4
Solve for y
y=\frac{3\left(x+4\right)}{8}
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-3x=12-8y
Subtract 8y from both sides.
\frac{-3x}{-3}=\frac{12-8y}{-3}
Divide both sides by -3.
x=\frac{12-8y}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{8y}{3}-4
Divide 12-8y by -3.
8y=12+3x
Add 3x to both sides.
8y=3x+12
The equation is in standard form.
\frac{8y}{8}=\frac{3x+12}{8}
Divide both sides by 8.
y=\frac{3x+12}{8}
Dividing by 8 undoes the multiplication by 8.
y=\frac{3x}{8}+\frac{3}{2}
Divide 12+3x by 8.
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