Solve for x
x=\frac{5\left(y-4\right)}{3}
Solve for y
y=\frac{3x}{5}+4
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-3x=20-5y
Subtract 5y from both sides.
\frac{-3x}{-3}=\frac{20-5y}{-3}
Divide both sides by -3.
x=\frac{20-5y}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{5y-20}{3}
Divide 20-5y by -3.
5y=20+3x
Add 3x to both sides.
5y=3x+20
The equation is in standard form.
\frac{5y}{5}=\frac{3x+20}{5}
Divide both sides by 5.
y=\frac{3x+20}{5}
Dividing by 5 undoes the multiplication by 5.
y=\frac{3x}{5}+4
Divide 20+3x by 5.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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