Solve -3s+27+[-12-18+2-1)-16^2s

$$- 3 s + 27 + [ - 12 - 18 + 2 - 1 ) - 16 ^ { 2 } s$$

Evaluate

$$-259s-2$$

Solution Steps

Subtract 12 from 27 to get 15.

$$-3s+15-18+2-1-16^{2}s$$

Subtract 18 from 15 to get -3.

$$-3s-3+2-1-16^{2}s$$

Add -3 and 2 to get -1.

$$-3s-1-1-16^{2}s$$

Subtract 1 from -1 to get -2.

$$-3s-2-16^{2}s$$

Calculate 16 to the power of 2 and get 256.

$$-3s-2-256s$$

Combine -3s and -256s to get -259s.

$$-259s-2$$

Differentiate w.r.t. s

$$-259$$

Steps Using Derivative Rule for Sum

Subtract 12 from 27 to get 15.

$$\frac{\mathrm{d}}{\mathrm{d}s}(-3s+15-18+2-1-16^{2}s)$$

Subtract 18 from 15 to get -3.

$$\frac{\mathrm{d}}{\mathrm{d}s}(-3s-3+2-1-16^{2}s)$$

Add -3 and 2 to get -1.

$$\frac{\mathrm{d}}{\mathrm{d}s}(-3s-1-1-16^{2}s)$$

Subtract 1 from -1 to get -2.

$$\frac{\mathrm{d}}{\mathrm{d}s}(-3s-2-16^{2}s)$$

Calculate 16 to the power of 2 and get 256.

$$\frac{\mathrm{d}}{\mathrm{d}s}(-3s-2-256s)$$

Combine -3s and -256s to get -259s.

$$\frac{\mathrm{d}}{\mathrm{d}s}(-259s-2)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-259s^{1-1}$$

Subtract 1 from 1.

$$-259s^{0}$$

For any term t except 0, t^{0}=1.

$$-259$$