Solve for m
m=-\frac{1}{3}+\frac{4}{3x}
x\neq 0
Solve for x
x=\frac{4}{3m+1}
m\neq -\frac{1}{3}
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-3mx+4=x
Add x to both sides. Anything plus zero gives itself.
-3mx=x-4
Subtract 4 from both sides.
\left(-3x\right)m=x-4
The equation is in standard form.
\frac{\left(-3x\right)m}{-3x}=\frac{x-4}{-3x}
Divide both sides by -3x.
m=\frac{x-4}{-3x}
Dividing by -3x undoes the multiplication by -3x.
m=-\frac{1}{3}+\frac{4}{3x}
Divide x-4 by -3x.
-3mx-x=-4
Subtract 4 from both sides. Anything subtracted from zero gives its negation.
\left(-3m-1\right)x=-4
Combine all terms containing x.
\frac{\left(-3m-1\right)x}{-3m-1}=-\frac{4}{-3m-1}
Divide both sides by -3m-1.
x=-\frac{4}{-3m-1}
Dividing by -3m-1 undoes the multiplication by -3m-1.
x=\frac{4}{3m+1}
Divide -4 by -3m-1.
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