Solve -3f(-3)=-2x^2(-3)+5(-3)

$$- 3 f ( - 3 ) = - 2 x ^ { 2 } ( - 3 ) + 5 ( - 3 )$$

Solve for f

$$f=\frac{2x^{2}-5}{3}$$

Steps for Solving Linear Equation

Multiply -3 and -3 to get 9.

$$9f=-2x^{2}\left(-3\right)+5\left(-3\right)$$

Multiply -2 and -3 to get 6.

$$9f=6x^{2}+5\left(-3\right)$$

Multiply 5 and -3 to get -15.

$$9f=6x^{2}-15$$

Divide both sides by 9.

$$\frac{9f}{9}=\frac{6x^{2}-15}{9}$$

Dividing by 9 undoes the multiplication by 9.

$$f=\frac{6x^{2}-15}{9}$$

Divide 6x^{2}-15 by 9.

$$f=\frac{2x^{2}-5}{3}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{6f+10}}{2}$$

$$x=\frac{\sqrt{6f+10}}{2}$$

Solve for x

$$x=\frac{\sqrt{6f+10}}{2}$$

$$x=-\frac{\sqrt{6f+10}}{2}\text{, }f\geq -\frac{5}{3}$$