Solve for A
A=\frac{D}{3}
Solve for D
D=3A
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-3A=-D
Subtract D from both sides. Anything subtracted from zero gives its negation.
\frac{-3A}{-3}=-\frac{D}{-3}
Divide both sides by -3.
A=-\frac{D}{-3}
Dividing by -3 undoes the multiplication by -3.
A=\frac{D}{3}
Divide -D by -3.
D=3A
Add 3A to both sides. Anything plus zero gives itself.
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Limits
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