Solve -3-4a=3p-2n

$$- 3 - 4 a = 3 p - 2 n$$

Solve for a

$$a=\frac{n}{2}-\frac{3p}{4}-\frac{3}{4}$$

Steps for Solving Linear Equation

Add 3 to both sides.

$$-4a=3p-2n+3$$

The equation is in standard form.

$$-4a=3+3p-2n$$

Divide both sides by -4.

$$\frac{-4a}{-4}=\frac{3+3p-2n}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$a=\frac{3+3p-2n}{-4}$$

Divide 3p-2n+3 by -4.

$$a=\frac{n}{2}-\frac{3p}{4}-\frac{3}{4}$$

Solve for n

$$n=\frac{3p}{2}+2a+\frac{3}{2}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$3p-2n=-3-4a$$

Subtract 3p from both sides.

$$-2n=-3-4a-3p$$

The equation is in standard form.

$$-2n=-3p-4a-3$$

Divide both sides by -2.

$$\frac{-2n}{-2}=\frac{-3p-4a-3}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$n=\frac{-3p-4a-3}{-2}$$

Divide -3-4a-3p by -2.

$$n=\frac{3p}{2}+2a+\frac{3}{2}$$