Solve -3(y-1)<2(9+y)

$$- 3 ( y - 1 ) < 2 ( 9 + y )$$

Solve for y

$$y>-3$$

Solution Steps

Use the distributive property to multiply -3 by y-1.

$$-3y+3<2\left(9+y\right)$$

Use the distributive property to multiply 2 by 9+y.

$$-3y+3<18+2y$$

Subtract 2y from both sides.

$$-3y+3-2y<18$$

Combine -3y and -2y to get -5y.

$$-5y+3<18$$

Subtract 3 from both sides.

$$-5y<18-3$$

Subtract 3 from 18 to get 15.

$$-5y<15$$

Divide both sides by -5. Since -5 is negative, the inequality direction is changed.

$$y>\frac{15}{-5}$$

Divide 15 by -5 to get -3.

$$y>-3$$