Solve -3(x+2)+39leq5(3-x)

$$- 3 ( x + 2 ) + 39 \leq 5 ( 3 - x )$$

Solve for x

$$x\leq -9$$

Solution Steps

Use the distributive property to multiply -3 by x+2.

$$-3x-6+39\leq 5\left(3-x\right)$$

Add -6 and 39 to get 33.

$$-3x+33\leq 5\left(3-x\right)$$

Use the distributive property to multiply 5 by 3-x.

$$-3x+33\leq 15-5x$$

Add 5x to both sides.

$$-3x+33+5x\leq 15$$

Combine -3x and 5x to get 2x.

$$2x+33\leq 15$$

Subtract 33 from both sides.

$$2x\leq 15-33$$

Subtract 33 from 15 to get -18.

$$2x\leq -18$$

Divide both sides by 2. Since 2 is positive, the inequality direction remains the same.

$$x\leq \frac{-18}{2}$$

Divide -18 by 2 to get -9.

$$x\leq -9$$