Solve -3(6y-3)geq3(4y-7)

$$- 3 ( 6 y - 3 ) \geq 3 ( 4 y - 7 )$$

Solve for y

$$y\leq 1$$

Solution Steps

Use the distributive property to multiply -3 by 6y-3.

$$-18y+9\geq 3\left(4y-7\right)$$

Use the distributive property to multiply 3 by 4y-7.

$$-18y+9\geq 12y-21$$

Subtract 12y from both sides.

$$-18y+9-12y\geq -21$$

Combine -18y and -12y to get -30y.

$$-30y+9\geq -21$$

Subtract 9 from both sides.

$$-30y\geq -21-9$$

Subtract 9 from -21 to get -30.

$$-30y\geq -30$$

Divide both sides by -30. Since -30 is negative, the inequality direction is changed.

$$y\leq \frac{-30}{-30}$$

Divide -30 by -30 to get 1.

$$y\leq 1$$