Solve -3(-20-j)<-4(-3j-6)

$$- 3 ( - 20 - j ) < - 4 ( - 3 j - 6 )$$

Solve for j

$$j>4$$

Solution Steps

Use the distributive property to multiply -3 by -20-j.

$$60+3j<-4\left(-3j-6\right)$$

Use the distributive property to multiply -4 by -3j-6.

$$60+3j<12j+24$$

Subtract 12j from both sides.

$$60+3j-12j<24$$

Combine 3j and -12j to get -9j.

$$60-9j<24$$

Subtract 60 from both sides.

$$-9j<24-60$$

Subtract 60 from 24 to get -36.

$$-9j<-36$$

Divide both sides by -9. Since -9 is negative, the inequality direction is changed.

$$j>\frac{-36}{-9}$$

Divide -36 by -9 to get 4.

$$j>4$$