Solve -3*(x-1/3)^2+27=0

$$- 3 \times ( x - \frac { 1 } { 3 } ) ^ { 2 } + 27 = 0$$

Solve for x

$$x = \frac{10}{3} = 3\frac{1}{3} \approx 3.333333333$$

$$x = -\frac{8}{3} = -2\frac{2}{3} \approx -2.666666667$$

Steps by Finding Square Root

Subtract 27 from both sides of the equation.

$$-3\left(x-\frac{1}{3}\right)^{2}+27-27=-27$$

Subtracting 27 from itself leaves 0.

$$-3\left(x-\frac{1}{3}\right)^{2}=-27$$

Divide both sides by -3.

$$\frac{-3\left(x-\frac{1}{3}\right)^{2}}{-3}=-\frac{27}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$\left(x-\frac{1}{3}\right)^{2}=-\frac{27}{-3}$$

Divide -27 by -3.

$$\left(x-\frac{1}{3}\right)^{2}=9$$

Take the square root of both sides of the equation.

$$x-\frac{1}{3}=3 x-\frac{1}{3}=-3$$

Add \frac{1}{3} to both sides of the equation.

$$x-\frac{1}{3}-\left(-\frac{1}{3}\right)=3-\left(-\frac{1}{3}\right) x-\frac{1}{3}-\left(-\frac{1}{3}\right)=-3-\left(-\frac{1}{3}\right)$$

Subtracting -\frac{1}{3} from itself leaves 0.

$$x=3-\left(-\frac{1}{3}\right) x=-3-\left(-\frac{1}{3}\right)$$

Subtract -\frac{1}{3} from 3.

$$x=\frac{10}{3}$$

Subtract -\frac{1}{3} from -3.

$$x=-\frac{8}{3}$$

The equation is now solved.

$$x=\frac{10}{3} x=-\frac{8}{3}$$