Solve -3*1/4+3*1/2+1

$$- 3 \times \frac { 1 } { 4 } + 3 \times \frac { 1 } { 2 } + 1$$

Evaluate

$$\frac{7}{4}=1.75$$

Solution Steps

Multiply -3 and \frac{1}{4} to get \frac{-3}{4}.

$$\frac{-3}{4}+3\times \frac{1}{2}+1$$

Fraction \frac{-3}{4} can be rewritten as -\frac{3}{4} by extracting the negative sign.

$$-\frac{3}{4}+3\times \frac{1}{2}+1$$

Multiply 3 and \frac{1}{2} to get \frac{3}{2}.

$$-\frac{3}{4}+\frac{3}{2}+1$$

Least common multiple of 4 and 2 is 4. Convert -\frac{3}{4} and \frac{3}{2} to fractions with denominator 4.

$$-\frac{3}{4}+\frac{6}{4}+1$$

Since -\frac{3}{4} and \frac{6}{4} have the same denominator, add them by adding their numerators.

$$\frac{-3+6}{4}+1$$

Add -3 and 6 to get 3.

$$\frac{3}{4}+1$$

Convert 1 to fraction \frac{4}{4}.

$$\frac{3}{4}+\frac{4}{4}$$

Since \frac{3}{4} and \frac{4}{4} have the same denominator, add them by adding their numerators.

$$\frac{3+4}{4}$$

Add 3 and 4 to get 7.

$$\frac{7}{4}$$

Factor

$$\frac{7}{2 ^ {2}} = 1\frac{3}{4} = 1.75$$