Solve -3^3-[8div(-2)^3-1]+(-3)^2*(-2)^3div1/-frac{1{2}}

$$- 3 ^ { 3 } - [ 8 \div ( - 2 ) ^ { 3 } - 1 ] + ( - 3 ) ^ { 2 } \times ( - 2 ) ^ { 3 } \div \frac { 1 } { - \frac { 1 } { 2 } }$$

Evaluate

$$11$$

Solution Steps

Calculate 3 to the power of 3 and get 27.

$$-27-\left(\frac{8}{\left(-2\right)^{3}}-1\right)+\frac{\left(-3\right)^{2}\left(-2\right)^{3}}{\frac{1}{-\frac{1}{2}}}$$

Calculate -2 to the power of 3 and get -8.

$$-27-\left(\frac{8}{-8}-1\right)+\frac{\left(-3\right)^{2}\left(-2\right)^{3}}{\frac{1}{-\frac{1}{2}}}$$

Divide 8 by -8 to get -1.

$$-27-\left(-1-1\right)+\frac{\left(-3\right)^{2}\left(-2\right)^{3}}{\frac{1}{-\frac{1}{2}}}$$

Subtract 1 from -1 to get -2.

$$-27-\left(-2\right)+\frac{\left(-3\right)^{2}\left(-2\right)^{3}}{\frac{1}{-\frac{1}{2}}}$$

The opposite of -2 is 2.

$$-27+2+\frac{\left(-3\right)^{2}\left(-2\right)^{3}}{\frac{1}{-\frac{1}{2}}}$$

Add -27 and 2 to get -25.

$$-25+\frac{\left(-3\right)^{2}\left(-2\right)^{3}}{\frac{1}{-\frac{1}{2}}}$$

Calculate -3 to the power of 2 and get 9.

$$-25+\frac{9\left(-2\right)^{3}}{\frac{1}{-\frac{1}{2}}}$$

Calculate -2 to the power of 3 and get -8.

$$-25+\frac{9\left(-8\right)}{\frac{1}{-\frac{1}{2}}}$$

Multiply 9 and -8 to get -72.

$$-25+\frac{-72}{\frac{1}{-\frac{1}{2}}}$$

Divide 1 by -\frac{1}{2} by multiplying 1 by the reciprocal of -\frac{1}{2}.

$$-25+\frac{-72}{1\left(-2\right)}$$

Multiply 1 and -2 to get -2.

$$-25+\frac{-72}{-2}$$

Divide -72 by -2 to get 36.

$$-25+36$$

Add -25 and 36 to get 11.

$$11$$

Factor

$$11$$