Solve -3^3*(-5)+16div(-2)^3-|-4*5|+(5/8-0625)^2

$$- 3 ^ { 3 } \times ( - 5 ) + 16 \div ( - 2 ) ^ { 3 } - | - 4 \times 5 | + ( \frac { 5 } { 8 } - 0625 ) ^ { 2 }$$

Evaluate

$$\frac{7257}{64}=113.390625$$

Solution Steps

Calculate 3 to the power of 3 and get 27.

$$-27\left(-5\right)+\frac{16}{\left(-2\right)^{3}}-|-4\times 5|+\left(\frac{5}{8}-0\times 625\right)^{2}$$

Multiply -27 and -5 to get 135.

$$135+\frac{16}{\left(-2\right)^{3}}-|-4\times 5|+\left(\frac{5}{8}-0\times 625\right)^{2}$$

Calculate -2 to the power of 3 and get -8.

$$135+\frac{16}{-8}-|-4\times 5|+\left(\frac{5}{8}-0\times 625\right)^{2}$$

Divide 16 by -8 to get -2.

$$135-2-|-4\times 5|+\left(\frac{5}{8}-0\times 625\right)^{2}$$

Subtract 2 from 135 to get 133.

$$133-|-4\times 5|+\left(\frac{5}{8}-0\times 625\right)^{2}$$

Multiply -4 and 5 to get -20.

$$133-|-20|+\left(\frac{5}{8}-0\times 625\right)^{2}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -20 is 20.

$$133-20+\left(\frac{5}{8}-0\times 625\right)^{2}$$

Subtract 20 from 133 to get 113.

$$113+\left(\frac{5}{8}-0\times 625\right)^{2}$$

Multiply 0 and 625 to get 0.

$$113+\left(\frac{5}{8}-0\right)^{2}$$

Subtract 0 from \frac{5}{8} to get \frac{5}{8}.

$$113+\left(\frac{5}{8}\right)^{2}$$

Calculate \frac{5}{8} to the power of 2 and get \frac{25}{64}.

$$113+\frac{25}{64}$$

Add 113 and \frac{25}{64} to get \frac{7257}{64}.

$$\frac{7257}{64}$$

Factor

$$\frac{3 \cdot 41 \cdot 59}{2 ^ {6}} = 113\frac{25}{64} = 113.390625$$