Solve -3^2-3/4*(-22/3)=

$$- 3 ^ { 2 } - \frac { 3 } { 4 } \times ( - 2 \frac { 2 } { 3 } ) =$$

Evaluate

$$-7$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$-9-\frac{3}{4}\left(-\frac{2\times 3+2}{3}\right)$$

Multiply 2 and 3 to get 6.

$$-9-\frac{3}{4}\left(-\frac{6+2}{3}\right)$$

Add 6 and 2 to get 8.

$$-9-\frac{3}{4}\left(-\frac{8}{3}\right)$$

Multiply \frac{3}{4} times -\frac{8}{3} by multiplying numerator times numerator and denominator times denominator.

$$-9-\frac{3\left(-8\right)}{4\times 3}$$

Cancel out 3 in both numerator and denominator.

$$-9-\frac{-8}{4}$$

Divide -8 by 4 to get -2.

$$-9-\left(-2\right)$$

The opposite of -2 is 2.

$$-9+2$$

Add -9 and 2 to get -7.

$$-7$$

Factor

$$-7$$