Solve -3^2-[4-6*8-3(2-sqrt{25})]-10

$$- 3 ^ { 2 } - [ 4 - 6 \cdot 8 - 3 ( 2 - \sqrt { 25 } ) ] - 10$$

Evaluate

$$16$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$-9-\left(4-6\times 8-3\left(2-\sqrt{25}\right)\right)-10$$

Multiply 6 and 8 to get 48.

$$-9-\left(4-48-3\left(2-\sqrt{25}\right)\right)-10$$

Subtract 48 from 4 to get -44.

$$-9-\left(-44-3\left(2-\sqrt{25}\right)\right)-10$$

Calculate the square root of 25 and get 5.

$$-9-\left(-44-3\left(2-5\right)\right)-10$$

Subtract 5 from 2 to get -3.

$$-9-\left(-44-3\left(-3\right)\right)-10$$

Multiply 3 and -3 to get -9.

$$-9-\left(-44-\left(-9\right)\right)-10$$

The opposite of -9 is 9.

$$-9-\left(-44+9\right)-10$$

Add -44 and 9 to get -35.

$$-9-\left(-35\right)-10$$

The opposite of -35 is 35.

$$-9+35-10$$

Add -9 and 35 to get 26.

$$26-10$$

Subtract 10 from 26 to get 16.

$$16$$

Factor

$$2^{4}$$