Solve -3^2quadtext{II}4.7^2-3^4:9

$$- 3 ^ { 2 } \quad \text { II } 4.7 ^ { 2 } - 3 ^ { 4 } : 9$$

Evaluate

$$-\frac{19881I^{2}}{100}-9$$

Solution Steps

Multiply I and I to get I^{2}.

$$\left(-3^{2}\right)I^{2}\times 4.7^{2}-\frac{3^{4}}{9}$$

Calculate 3 to the power of 2 and get 9.

$$-9I^{2}\times 4.7^{2}-\frac{3^{4}}{9}$$

Calculate 4.7 to the power of 2 and get 22.09.

$$-9I^{2}\times 22.09-\frac{3^{4}}{9}$$

Multiply -9 and 22.09 to get -198.81.

$$-198.81I^{2}-\frac{3^{4}}{9}$$

Calculate 3 to the power of 4 and get 81.

$$-198.81I^{2}-\frac{81}{9}$$

Divide 81 by 9 to get 9.

$$-198.81I^{2}-9$$

Factor

$$-\frac{9\left(2209I^{2}+100\right)}{100}$$