Solve -3^2div21/4*[-2/3]+4+2^2*(-3/3)

$$- 3 ^ { 2 } \div 2 \frac { 1 } { 4 } \times [ - \frac { 2 } { 3 } ] + 4 + 2 ^ { 2 } \times ( - \frac { 3 } { 3 } )$$

Evaluate

$$\frac{8}{3}\approx 2.666666667$$

Solution Steps

Divide 3 by 3 to get 1.

$$\frac{-3^{2}}{\frac{2\times 4+1}{4}}\left(-\frac{2}{3}\right)+4+2^{2}\left(-1\right)$$

Calculate 3 to the power of 2 and get 9.

$$\frac{-9}{\frac{2\times 4+1}{4}}\left(-\frac{2}{3}\right)+4+2^{2}\left(-1\right)$$

Multiply 2 and 4 to get 8.

$$\frac{-9}{\frac{8+1}{4}}\left(-\frac{2}{3}\right)+4+2^{2}\left(-1\right)$$

Add 8 and 1 to get 9.

$$\frac{-9}{\frac{9}{4}}\left(-\frac{2}{3}\right)+4+2^{2}\left(-1\right)$$

Divide -9 by \frac{9}{4} by multiplying -9 by the reciprocal of \frac{9}{4}.

$$-9\times \frac{4}{9}\left(-\frac{2}{3}\right)+4+2^{2}\left(-1\right)$$

Multiply -9 times \frac{4}{9}.

$$-4\left(-\frac{2}{3}\right)+4+2^{2}\left(-1\right)$$

Express -4\left(-\frac{2}{3}\right) as a single fraction.

$$\frac{-4\left(-2\right)}{3}+4+2^{2}\left(-1\right)$$

Multiply -4 and -2 to get 8.

$$\frac{8}{3}+4+2^{2}\left(-1\right)$$

Convert 4 to fraction \frac{12}{3}.

$$\frac{8}{3}+\frac{12}{3}+2^{2}\left(-1\right)$$

Since \frac{8}{3} and \frac{12}{3} have the same denominator, add them by adding their numerators.

$$\frac{8+12}{3}+2^{2}\left(-1\right)$$

Add 8 and 12 to get 20.

$$\frac{20}{3}+2^{2}\left(-1\right)$$

Calculate 2 to the power of 2 and get 4.

$$\frac{20}{3}+4\left(-1\right)$$

Multiply 4 and -1 to get -4.

$$\frac{20}{3}-4$$

Convert 4 to fraction \frac{12}{3}.

$$\frac{20}{3}-\frac{12}{3}$$

Since \frac{20}{3} and \frac{12}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{20-12}{3}$$

Subtract 12 from 20 to get 8.

$$\frac{8}{3}$$

Factor

$$\frac{2 ^ {3}}{3} = 2\frac{2}{3} = 2.6666666666666665$$