Solve -3^2+(-3)^2-(-3^2)-5^2*2/5

$$- 3 ^ { 2 } + ( - 3 ) ^ { 2 } - ( - 3 ^ { 2 } ) - 5 ^ { 2 } \times \frac { 2 } { 5 }$$

Evaluate

$$-1$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$-9+\left(-3\right)^{2}-\left(-3^{2}\right)-5^{2}\times \frac{2}{5}$$

Calculate -3 to the power of 2 and get 9.

$$-9+9-\left(-3^{2}\right)-5^{2}\times \frac{2}{5}$$

Add -9 and 9 to get 0.

$$0-\left(-3^{2}\right)-5^{2}\times \frac{2}{5}$$

Calculate 3 to the power of 2 and get 9.

$$0-\left(-9\right)-5^{2}\times \frac{2}{5}$$

The opposite of -9 is 9.

$$0+9-5^{2}\times \frac{2}{5}$$

Add 0 and 9 to get 9.

$$9-5^{2}\times \frac{2}{5}$$

Calculate 5 to the power of 2 and get 25.

$$9-25\times \frac{2}{5}$$

Express 25\times \frac{2}{5} as a single fraction.

$$9-\frac{25\times 2}{5}$$

Multiply 25 and 2 to get 50.

$$9-\frac{50}{5}$$

Divide 50 by 5 to get 10.

$$9-10$$

Subtract 10 from 9 to get -1.

$$-1$$

Factor

$$-1$$