Solve -3^2+(-025)^100*4^100+(1/2-1/3)*(1/6)^-2

$$- 3 ^ { 2 } + ( - 025 ) ^ { 100 } \times 4 ^ { 100 } + ( \frac { 1 } { 2 } - \frac { 1 } { 3 } ) \times ( \frac { 1 } { 6 } ) ^ { - 2 }$$

Evaluate

$$-3$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$-9+\left(0\times 25\right)^{100}\times 4^{100}+\left(\frac{1}{2}-\frac{1}{3}\right)\times \left(\frac{1}{6}\right)^{-2}$$

Multiply 0 and 25 to get 0.

$$-9+0^{100}\times 4^{100}+\left(\frac{1}{2}-\frac{1}{3}\right)\times \left(\frac{1}{6}\right)^{-2}$$

Calculate 0 to the power of 100 and get 0.

$$-9+0\times 4^{100}+\left(\frac{1}{2}-\frac{1}{3}\right)\times \left(\frac{1}{6}\right)^{-2}$$

Calculate 4 to the power of 100 and get 1606938044258990275541962092341162602522202993782792835301376.

$$-9+0\times 1606938044258990275541962092341162602522202993782792835301376+\left(\frac{1}{2}-\frac{1}{3}\right)\times \left(\frac{1}{6}\right)^{-2}$$

Multiply 0 and 1606938044258990275541962092341162602522202993782792835301376 to get 0.

$$-9+0+\left(\frac{1}{2}-\frac{1}{3}\right)\times \left(\frac{1}{6}\right)^{-2}$$

Add -9 and 0 to get -9.

$$-9+\left(\frac{1}{2}-\frac{1}{3}\right)\times \left(\frac{1}{6}\right)^{-2}$$

Subtract \frac{1}{3} from \frac{1}{2} to get \frac{1}{6}.

$$-9+\frac{1}{6}\times \left(\frac{1}{6}\right)^{-2}$$

Calculate \frac{1}{6} to the power of -2 and get 36.

$$-9+\frac{1}{6}\times 36$$

Multiply \frac{1}{6} and 36 to get 6.

$$-9+6$$

Add -9 and 6 to get -3.

$$-3$$

Factor

$$-3$$