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Solve for x (complex solution)
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x^{2}+x=-3
Swap sides so that all variable terms are on the left hand side.
x^{2}+x+3=0
Add 3 to both sides.
x=\frac{-1±\sqrt{1^{2}-4\times 3}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 1 for b, and 3 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-1±\sqrt{1-4\times 3}}{2}
Square 1.
x=\frac{-1±\sqrt{1-12}}{2}
Multiply -4 times 3.
x=\frac{-1±\sqrt{-11}}{2}
Add 1 to -12.
x=\frac{-1±\sqrt{11}i}{2}
Take the square root of -11.
x=\frac{-1+\sqrt{11}i}{2}
Now solve the equation x=\frac{-1±\sqrt{11}i}{2} when ± is plus. Add -1 to i\sqrt{11}.
x=\frac{-\sqrt{11}i-1}{2}
Now solve the equation x=\frac{-1±\sqrt{11}i}{2} when ± is minus. Subtract i\sqrt{11} from -1.
x=\frac{-1+\sqrt{11}i}{2} x=\frac{-\sqrt{11}i-1}{2}
The equation is now solved.
x^{2}+x=-3
Swap sides so that all variable terms are on the left hand side.
x^{2}+x+\left(\frac{1}{2}\right)^{2}=-3+\left(\frac{1}{2}\right)^{2}
Divide 1, the coefficient of the x term, by 2 to get \frac{1}{2}. Then add the square of \frac{1}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+x+\frac{1}{4}=-3+\frac{1}{4}
Square \frac{1}{2} by squaring both the numerator and the denominator of the fraction.
x^{2}+x+\frac{1}{4}=-\frac{11}{4}
Add -3 to \frac{1}{4}.
\left(x+\frac{1}{2}\right)^{2}=-\frac{11}{4}
Factor x^{2}+x+\frac{1}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{1}{2}\right)^{2}}=\sqrt{-\frac{11}{4}}
Take the square root of both sides of the equation.
x+\frac{1}{2}=\frac{\sqrt{11}i}{2} x+\frac{1}{2}=-\frac{\sqrt{11}i}{2}
Simplify.
x=\frac{-1+\sqrt{11}i}{2} x=\frac{-\sqrt{11}i-1}{2}
Subtract \frac{1}{2} from both sides of the equation.