Solve -3(-2)^{2}-2^2+[(-2)^5:2^4*(-1-98)^0]=

$$- 3 ( - 2 ) ^ { 2 } - 2 ^ { 2 } + [ ( - 2 ) ^ { 5 } : 2 ^ { 4 } \cdot ( - 1 - 98 ) ^ { 0 } ] =$$

Evaluate

$$-18$$

Solution Steps

Calculate -2 to the power of 2 and get 4.

$$-3\times 4-2^{2}+\frac{\left(-2\right)^{5}}{2^{4}}\left(-1-98\right)^{0}$$

Multiply -3 and 4 to get -12.

$$-12-2^{2}+\frac{\left(-2\right)^{5}}{2^{4}}\left(-1-98\right)^{0}$$

Calculate 2 to the power of 2 and get 4.

$$-12-4+\frac{\left(-2\right)^{5}}{2^{4}}\left(-1-98\right)^{0}$$

Subtract 4 from -12 to get -16.

$$-16+\frac{\left(-2\right)^{5}}{2^{4}}\left(-1-98\right)^{0}$$

Calculate -2 to the power of 5 and get -32.

$$-16+\frac{-32}{2^{4}}\left(-1-98\right)^{0}$$

Calculate 2 to the power of 4 and get 16.

$$-16+\frac{-32}{16}\left(-1-98\right)^{0}$$

Divide -32 by 16 to get -2.

$$-16-2\left(-1-98\right)^{0}$$

Subtract 98 from -1 to get -99.

$$-16-2\left(-99\right)^{0}$$

Calculate -99 to the power of 0 and get 1.

$$-16-2$$

Subtract 2 from -16 to get -18.

$$-18$$

Factor

$$-18$$