Solve -26-2sqrt{49}+(10g_{2}128*64-3*6)

$$- 26 - 2 \sqrt { 49 } + ( 10 g _ { 2 } 128 * 64 - 3 * 6 )$$

Evaluate

$$81920g_{2}-58$$

Solution Steps

Calculate the square root of 49 and get 7.

$$-26-2\times 7+10g_{2}\times 128\times 64-3\times 6$$

Multiply -2 and 7 to get -14.

$$-26-14+10g_{2}\times 128\times 64-3\times 6$$

Subtract 14 from -26 to get -40.

$$-40+10g_{2}\times 128\times 64-3\times 6$$

Multiply 10 and 128 to get 1280.

$$-40+1280g_{2}\times 64-3\times 6$$

Multiply 1280 and 64 to get 81920.

$$-40+81920g_{2}-3\times 6$$

Multiply 3 and 6 to get 18.

$$-40+81920g_{2}-18$$

Subtract 18 from -40 to get -58.

$$-58+81920g_{2}$$

Factor

$$2\left(40960g_{2}-29\right)$$

Solution Steps

Factor out 2.

$$2\left(-29+40960g_{2}\right)$$