Solve -2.1quad(4)3-y

$$- 2.1 \quad ( 4 ) 3 - y$$

Evaluate

$$-y-25.2$$

Solution Steps

Multiply -2.1 and 4 to get -8.4.

$$-8.4\times 3-y$$

Multiply -8.4 and 3 to get -25.2.

$$-25.2-y$$

Differentiate w.r.t. y

$$-1$$

Steps Using Derivative Rule for Sum

Multiply -2.1 and 4 to get -8.4.

$$\frac{\mathrm{d}}{\mathrm{d}y}(-8.4\times 3-y)$$

Multiply -8.4 and 3 to get -25.2.

$$\frac{\mathrm{d}}{\mathrm{d}y}(-25.2-y)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-y^{1-1}$$

Subtract 1 from 1.

$$-y^{0}$$

For any term t except 0, t^{0}=1.

$$-1$$