Solve -2y-3+4+3y

$$- 2 y - 3 + 4 + 3 y$$

Evaluate

$$y+1$$

Solution Steps

Add -3 and 4 to get 1.

$$-2y+1+3y$$

Combine -2y and 3y to get y.

$$y+1$$

Differentiate w.r.t. y

$$1$$

Steps Using Derivative Rule for Sum

Add -3 and 4 to get 1.

$$\frac{\mathrm{d}}{\mathrm{d}y}(-2y+1+3y)$$

Combine -2y and 3y to get y.

$$\frac{\mathrm{d}}{\mathrm{d}y}(y+1)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$y^{1-1}$$

Subtract 1 from 1.

$$y^{0}$$

For any term t except 0, t^{0}=1.

$$1$$