Solve for y
y=\frac{3\left(z-25\right)}{2}
Solve for z
z=\frac{2y}{3}+25
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-2y=75-3z
Subtract 3z from both sides.
\frac{-2y}{-2}=\frac{75-3z}{-2}
Divide both sides by -2.
y=\frac{75-3z}{-2}
Dividing by -2 undoes the multiplication by -2.
y=\frac{3z-75}{2}
Divide 75-3z by -2.
3z=75+2y
Add 2y to both sides.
3z=2y+75
The equation is in standard form.
\frac{3z}{3}=\frac{2y+75}{3}
Divide both sides by 3.
z=\frac{2y+75}{3}
Dividing by 3 undoes the multiplication by 3.
z=\frac{2y}{3}+25
Divide 75+2y by 3.
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