Solve -2x_{c}-6(y_{c}-3)=0

$$- 2 x _ { c } - 6 ( y _ { c } - 3 ) = 0$$

Solve for x_c

$$x_{c}=9-3y_{c}$$

Steps for Solving Linear Equation

Use the distributive property to multiply -6 by y_{c}-3.

$$-2x_{c}-6y_{c}+18=0$$

Add 6y_{c} to both sides. Anything plus zero gives itself.

$$-2x_{c}+18=6y_{c}$$

Subtract 18 from both sides.

$$-2x_{c}=6y_{c}-18$$

Divide both sides by -2.

$$\frac{-2x_{c}}{-2}=\frac{6y_{c}-18}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$x_{c}=\frac{6y_{c}-18}{-2}$$

Divide -18+6y_{c} by -2.

$$x_{c}=9-3y_{c}$$

Solve for y_c

$$y_{c}=-\frac{x_{c}}{3}+3$$

Steps for Solving Linear Equation

Use the distributive property to multiply -6 by y_{c}-3.

$$-2x_{c}-6y_{c}+18=0$$

Add 2x_{c} to both sides. Anything plus zero gives itself.

$$-6y_{c}+18=2x_{c}$$

Subtract 18 from both sides.

$$-6y_{c}=2x_{c}-18$$

Divide both sides by -6.

$$\frac{-6y_{c}}{-6}=\frac{2x_{c}-18}{-6}$$

Dividing by -6 undoes the multiplication by -6.

$$y_{c}=\frac{2x_{c}-18}{-6}$$

Divide -18+2x_{c} by -6.

$$y_{c}=-\frac{x_{c}}{3}+3$$